If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1;4;2;5;1;0
(x^2-4)*(x^2-(4*x)+4)*(x^2-(6*x)+8)*(x^2+4*x+4) < 0
2;7;5;3;0;0
(x^3)/(3-x^2)
2;11;5;9;1;2
| -23=x-45 | | 3h+1=5h-15 | | X^3-2x^2-3x-1056=0 | | 62.5*12.17=x | | -35=x-27 | | 75+25x=0 | | 26=19+x | | 14k=-280 | | 54-1b=48+1b | | 12x*5x=132 | | -37=x-56 | | 12x+5y=71 | | 7b^2-8b+4=0 | | 13x+6y=75 | | -26=x-56 | | 20=5a+4 | | 16+s=-90 | | -13=x+35 | | x-.25(2x+15)=.75 | | Y=-4.9x^2+10x | | 4x-(8-6x)= | | 8k-15=24 | | 19+.17x=520 | | 15j+6=6j-6 | | -45=x+37 | | 100/69.15=8n | | 3(-6+x)=x(5-3) | | 16x^2-128x+64=0 | | 10x^4-19x^2+7=0 | | 8x-5y=-13 | | 6m-(5-9m)=13 | | 4x+12=-5x-20 |